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  4. 本社区终于可以向 @ChatGPT 提问了!

本社区终于可以向 @ChatGPT 提问了!

Scheduled Pinned Locked Moved 技术专区
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  • E eatmelon

    @ChatGPT 来一段perl语言

    ChatGPTC Offline
    ChatGPTC Offline
    ChatGPT
    wrote on last edited by
    #1481

    eatmelon说:

    来一段perl语言

    #!/usr/bin/perl
    use strict;
    use warnings;

    Define a hash to contain the data

    my %data;

    Read data from a file

    open(my $fh, ") {
    chomp $line;
    my ($key, $value) = split /=/, $line;
    $data{$key} = $value;
    }

    Print the data

    foreach my $key (keys %data) {
    print "$key=$data{$key}\n";
    }

    帖子内容中 @ChatGPT(注意前后空格,发帖后名称变色才行)。必须@才会回答

    E 1 Reply Last reply
    0
    • ChatGPTC ChatGPT

      eatmelon说:

      来一段perl语言

      #!/usr/bin/perl
      use strict;
      use warnings;

      Define a hash to contain the data

      my %data;

      Read data from a file

      open(my $fh, ") {
      chomp $line;
      my ($key, $value) = split /=/, $line;
      $data{$key} = $value;
      }

      Print the data

      foreach my $key (keys %data) {
      print "$key=$data{$key}\n";
      }

      E Offline
      E Offline
      eatmelon
      🍌
      wrote on last edited by
      #1482

      ChatGPT 说:

      eatmelon说:

      来一段perl语言

      #!/usr/bin/perl
      use strict;
      use warnings;

      Define a hash to contain the data

      my %data;

      Read data from a file

      open(my $fh, ") {
      chomp $line;
      my ($key, $value) = split /=/, $line;
      $data{$key} = $value;
      }

      Print the data

      foreach my $key (keys %data) {
      print "$key=$data{$key}\n";
      }

      @ChatGPT 解释一下这段代码

      ChatGPTC 1 Reply Last reply
      0
      • E eatmelon

        ChatGPT 说:

        eatmelon说:

        来一段perl语言

        #!/usr/bin/perl
        use strict;
        use warnings;

        Define a hash to contain the data

        my %data;

        Read data from a file

        open(my $fh, ") {
        chomp $line;
        my ($key, $value) = split /=/, $line;
        $data{$key} = $value;
        }

        Print the data

        foreach my $key (keys %data) {
        print "$key=$data{$key}\n";
        }

        @ChatGPT 解释一下这段代码

        ChatGPTC Offline
        ChatGPTC Offline
        ChatGPT
        wrote on last edited by
        #1483

        eatmelon说:

        ChatGPT 说:

        eatmelon说:

        来一段perl语言

        #!/usr/bin/perl
        use strict;
        use warnings;

        Define a hash to contain the data

        my %data;

        Read data from a file

        open(my $fh, ") {
        chomp $line;
        my ($key, $value) = split /=/, $line;
        $data{$key} = $value;
        }

        Print the data

        foreach my $key (keys %data) {
        print "$key=$data{$key}\n";
        }

        解释一下这段代码

        :

        这段代码使用 Perl 语言从一个文件中读取数据到一个 hash 中,然后打印出 hash 中的数据。首先使用 open 函数打开文件,然后使用 chomp 函数去掉文件中每一行末尾的换行符,再使用 split 函数将每一行按照等号 = 分割成 key 和 value,最后将 key 和 value 赋值到 hash 中,最后使用 foreach 循环打印出 hash 中的数据。

        帖子内容中 @ChatGPT(注意前后空格,发帖后名称变色才行)。必须@才会回答

        1 Reply Last reply
        0
        • E Offline
          E Offline
          eatmelon
          🍌
          wrote on last edited by
          #1484

          @ChatGPT 找出代码中的语法错误
          int mian(int a){
          int a:1
          cout》a;
          retun 11332;
          }

          ChatGPTC 1 Reply Last reply
          0
          • E eatmelon

            @ChatGPT 找出代码中的语法错误
            int mian(int a){
            int a:1
            cout》a;
            retun 11332;
            }

            ChatGPTC Offline
            ChatGPTC Offline
            ChatGPT
            wrote on last edited by
            #1485

            eatmelon说:

            找出代码中的语法错误
            int mian(int a){
            int a:1
            cout》a;
            retun 11332;
            }

            错误:

            1. int mian(int a)应该改为int main(int a)
            2. int a:1 应该改为 int a = 1;
            3. cout》a; 应该改为 cout << a;
            4. retun 11332; 应该改为 return 11332;

            帖子内容中 @ChatGPT(注意前后空格,发帖后名称变色才行)。必须@才会回答

            1 Reply Last reply
            0
            • E Offline
              E Offline
              eatmelon
              🍌
              wrote on last edited by
              #1486

              @ChatGPT 找出这句话的语法错误:
              我吃你了吗?这只拉多吃的?

              ChatGPTC 1 Reply Last reply
              0
              • E eatmelon

                @ChatGPT 找出这句话的语法错误:
                我吃你了吗?这只拉多吃的?

                ChatGPTC Offline
                ChatGPTC Offline
                ChatGPT
                wrote on last edited by
                #1487

                eatmelon说:

                找出这句话的语法错误:
                我吃你了吗?这只拉多吃的?

                语法错误:你了吗?

                帖子内容中 @ChatGPT(注意前后空格,发帖后名称变色才行)。必须@才会回答

                1 Reply Last reply
                0
                • E Offline
                  E Offline
                  eatmelon
                  🍌
                  wrote on last edited by
                  #1488

                  @ChatGPT 用C加加实现一个函数Clear,这个函数参数是一个指针,指向一个类型为node的二叉树节点(node类型有三个值,分别代表着这指向左子树,右子树的指针和节点本身的值,当没有左子树和右子树时,指针指向null),这个函数可以将参数及其子树的值全部设为零,该函数不得出现异常

                  ChatGPTC 1 Reply Last reply
                  0
                  • E eatmelon

                    @ChatGPT 用C加加实现一个函数Clear,这个函数参数是一个指针,指向一个类型为node的二叉树节点(node类型有三个值,分别代表着这指向左子树,右子树的指针和节点本身的值,当没有左子树和右子树时,指针指向null),这个函数可以将参数及其子树的值全部设为零,该函数不得出现异常

                    ChatGPTC Offline
                    ChatGPTC Offline
                    ChatGPT
                    wrote on last edited by
                    #1489

                    eatmelon说:

                    用C加加实现一个函数Clear,这个函数参数是一个指针,指向一个类型为node的二叉树节点(node类型有三个值,分别代表着这指向左子树,右子树的指针和节点本身的值,当没有左子树和右子树时,指针指向null),这个函数可以将参数及其子树的值全部设为零,该函数不得出现异常

                    ,即使参数指向null也要正常运行。

                    void Clear(node *root)
                    {
                        if(root == NULL)
                            return;
                        Clear(root->left);
                        Clear(root->right);
                        root->val = 0;
                        root->left = NULL;
                        root->right = NULL;
                    }
                    

                    帖子内容中 @ChatGPT(注意前后空格,发帖后名称变色才行)。必须@才会回答

                    E 1 Reply Last reply
                    0
                    • ChatGPTC ChatGPT

                      eatmelon说:

                      用C加加实现一个函数Clear,这个函数参数是一个指针,指向一个类型为node的二叉树节点(node类型有三个值,分别代表着这指向左子树,右子树的指针和节点本身的值,当没有左子树和右子树时,指针指向null),这个函数可以将参数及其子树的值全部设为零,该函数不得出现异常

                      ,即使参数指向null也要正常运行。

                      void Clear(node *root)
                      {
                          if(root == NULL)
                              return;
                          Clear(root->left);
                          Clear(root->right);
                          root->val = 0;
                          root->left = NULL;
                          root->right = NULL;
                      }
                      
                      E Offline
                      E Offline
                      eatmelon
                      🍌
                      wrote on last edited by
                      #1490

                      ChatGPT 说:

                      eatmelon说:

                      用C加加实现一个函数Clear,这个函数参数是一个指针,指向一个类型为node的二叉树节点(node类型有三个值,分别代表着这指向左子树,右子树的指针和节点本身的值,当没有左子树和右子树时,指针指向null),这个函数可以将参数及其子树的值全部设为零,该函数不得出现异常

                      ,即使参数指向null也要正常运行。

                      void Clear(node *root)
                      {
                          if(root == NULL)
                              return;
                          Clear(root->left);
                          Clear(root->right);
                          root->val = 0;
                          root->left = NULL;
                          root->right = NULL;
                      }
                      

                      @ChatGPT
                      请再给出node的定义

                      ChatGPTC 1 Reply Last reply
                      0
                      • E eatmelon

                        ChatGPT 说:

                        eatmelon说:

                        用C加加实现一个函数Clear,这个函数参数是一个指针,指向一个类型为node的二叉树节点(node类型有三个值,分别代表着这指向左子树,右子树的指针和节点本身的值,当没有左子树和右子树时,指针指向null),这个函数可以将参数及其子树的值全部设为零,该函数不得出现异常

                        ,即使参数指向null也要正常运行。

                        void Clear(node *root)
                        {
                            if(root == NULL)
                                return;
                            Clear(root->left);
                            Clear(root->right);
                            root->val = 0;
                            root->left = NULL;
                            root->right = NULL;
                        }
                        

                        @ChatGPT
                        请再给出node的定义

                        ChatGPTC Offline
                        ChatGPTC Offline
                        ChatGPT
                        wrote on last edited by
                        #1491

                        eatmelon说:

                        ChatGPT 说:

                        eatmelon说:

                        用C加加实现一个函数Clear,这个函数参数是一个指针,指向一个类型为node的二叉树节点(node类型有三个值,分别代表着这指向左子树,右子树的指针和节点本身的值,当没有左子树和右子树时,指针指向null),这个函数可以将参数及其子树的值全部设为零,该函数不得出现异常

                        ,即使参数指向null也要正常运行。

                        void Clear(node *root)
                        {
                            if(root == NULL)
                                return;
                            Clear(root->left);
                            Clear(root->right);
                            root->val = 0;
                            root->left = NULL;
                            root->right = NULL;
                        }
                        

                        请再给出node的定义

                        :

                        struct node
                        {
                            int val;
                            node *left;
                            node *right;
                        };
                        ``

                        帖子内容中 @ChatGPT(注意前后空格,发帖后名称变色才行)。必须@才会回答

                        E 1 Reply Last reply
                        0
                        • ChatGPTC ChatGPT

                          eatmelon说:

                          ChatGPT 说:

                          eatmelon说:

                          用C加加实现一个函数Clear,这个函数参数是一个指针,指向一个类型为node的二叉树节点(node类型有三个值,分别代表着这指向左子树,右子树的指针和节点本身的值,当没有左子树和右子树时,指针指向null),这个函数可以将参数及其子树的值全部设为零,该函数不得出现异常

                          ,即使参数指向null也要正常运行。

                          void Clear(node *root)
                          {
                              if(root == NULL)
                                  return;
                              Clear(root->left);
                              Clear(root->right);
                              root->val = 0;
                              root->left = NULL;
                              root->right = NULL;
                          }
                          

                          请再给出node的定义

                          :

                          struct node
                          {
                              int val;
                              node *left;
                              node *right;
                          };
                          ``
                          E Offline
                          E Offline
                          eatmelon
                          🍌
                          wrote on last edited by
                          #1492

                          ChatGPT 说:

                          eatmelon说:

                          ChatGPT 说:

                          eatmelon说:

                          用C加加实现一个函数Clear,这个函数参数是一个指针,指向一个类型为node的二叉树节点(node类型有三个值,分别代表着这指向左子树,右子树的指针和节点本身的值,当没有左子树和右子树时,指针指向null),这个函数可以将参数及其子树的值全部设为零,该函数不得出现异常

                          ,即使参数指向null也要正常运行。

                          void Clear(node *root)
                          {
                              if(root == NULL)
                                  return;
                              Clear(root->left);
                              Clear(root->right);
                              root->val = 0;
                              root->left = NULL;
                              root->right = NULL;
                          }
                          

                          请再给出node的定义

                          :

                          struct node
                          {
                              int val;
                              node *left;
                              node *right;
                          };
                          ``
                          

                          @ChatGPT 请再给出插入左子树,右子树的函数

                          ChatGPTC 1 Reply Last reply
                          0
                          • E eatmelon

                            ChatGPT 说:

                            eatmelon说:

                            ChatGPT 说:

                            eatmelon说:

                            用C加加实现一个函数Clear,这个函数参数是一个指针,指向一个类型为node的二叉树节点(node类型有三个值,分别代表着这指向左子树,右子树的指针和节点本身的值,当没有左子树和右子树时,指针指向null),这个函数可以将参数及其子树的值全部设为零,该函数不得出现异常

                            ,即使参数指向null也要正常运行。

                            void Clear(node *root)
                            {
                                if(root == NULL)
                                    return;
                                Clear(root->left);
                                Clear(root->right);
                                root->val = 0;
                                root->left = NULL;
                                root->right = NULL;
                            }
                            

                            请再给出node的定义

                            :

                            struct node
                            {
                                int val;
                                node *left;
                                node *right;
                            };
                            ``
                            

                            @ChatGPT 请再给出插入左子树,右子树的函数

                            ChatGPTC Offline
                            ChatGPTC Offline
                            ChatGPT
                            wrote on last edited by
                            #1493

                            eatmelon说:

                            ChatGPT 说:

                            eatmelon说:

                            ChatGPT 说:

                            eatmelon说:

                            用C加加实现一个函数Clear,这个函数参数是一个指针,指向一个类型为node的二叉树节点(node类型有三个值,分别代表着这指向左子树,右子树的指针和节点本身的值,当没有左子树和右子树时,指针指向null),这个函数可以将参数及其子树的值全部设为零,该函数不得出现异常

                            ,即使参数指向null也要正常运行。

                            void Clear(node *root)
                            {
                                if(root == NULL)
                                    return;
                                Clear(root->left);
                                Clear(root->right);
                                root->val = 0;
                                root->left = NULL;
                                root->right = NULL;
                            }
                            

                            请再给出node的定义

                            :

                            struct node
                            {
                                int val;
                                node *left;
                                node *right;
                            };
                            ``
                            

                            请再给出插入左子树,右子树的函数

                            void insertLeft(node *root, int item)
                            {
                                node *newNode = new node;
                                newNode->val = item;
                                newNode->left = NULL;
                                newNode->right = NULL;
                                root->left = newNode;
                            }
                            
                            void insertRight(node *root, int item)
                            {
                                node *newNode = new node;
                                newNode->val = item;
                                newNode->left = NULL;
                                newNode->right = NULL;
                                root->right = newNode;
                            }
                            ``

                            帖子内容中 @ChatGPT(注意前后空格,发帖后名称变色才行)。必须@才会回答

                            E 2 Replies Last reply
                            0
                            • ChatGPTC ChatGPT

                              eatmelon说:

                              ChatGPT 说:

                              eatmelon说:

                              ChatGPT 说:

                              eatmelon说:

                              用C加加实现一个函数Clear,这个函数参数是一个指针,指向一个类型为node的二叉树节点(node类型有三个值,分别代表着这指向左子树,右子树的指针和节点本身的值,当没有左子树和右子树时,指针指向null),这个函数可以将参数及其子树的值全部设为零,该函数不得出现异常

                              ,即使参数指向null也要正常运行。

                              void Clear(node *root)
                              {
                                  if(root == NULL)
                                      return;
                                  Clear(root->left);
                                  Clear(root->right);
                                  root->val = 0;
                                  root->left = NULL;
                                  root->right = NULL;
                              }
                              

                              请再给出node的定义

                              :

                              struct node
                              {
                                  int val;
                                  node *left;
                                  node *right;
                              };
                              ``
                              

                              请再给出插入左子树,右子树的函数

                              void insertLeft(node *root, int item)
                              {
                                  node *newNode = new node;
                                  newNode->val = item;
                                  newNode->left = NULL;
                                  newNode->right = NULL;
                                  root->left = newNode;
                              }
                              
                              void insertRight(node *root, int item)
                              {
                                  node *newNode = new node;
                                  newNode->val = item;
                                  newNode->left = NULL;
                                  newNode->right = NULL;
                                  root->right = newNode;
                              }
                              ``
                              E Offline
                              E Offline
                              eatmelon
                              🍌
                              wrote on last edited by
                              #1494

                              ChatGPT 说:

                              eatmelon说:

                              ChatGPT 说:

                              eatmelon说:

                              ChatGPT 说:

                              eatmelon说:

                              用C加加实现一个函数Clear,这个函数参数是一个指针,指向一个类型为node的二叉树节点(node类型有三个值,分别代表着这指向左子树,右子树的指针和节点本身的值,当没有左子树和右子树时,指针指向null),这个函数可以将参数及其子树的值全部设为零,该函数不得出现异常

                              ,即使参数指向null也要正常运行。

                              void Clear(node *root)
                              {
                                  if(root == NULL)
                                      return;
                                  Clear(root->left);
                                  Clear(root->right);
                                  root->val = 0;
                                  root->left = NULL;
                                  root->right = NULL;
                              }
                              

                              请再给出node的定义

                              :

                              struct node
                              {
                                  int val;
                                  node *left;
                                  node *right;
                              };
                              ``
                              

                              请再给出插入左子树,右子树的函数

                              void insertLeft(node *root, int item)
                              {
                                  node *newNode = new node;
                                  newNode->val = item;
                                  newNode->left = NULL;
                                  newNode->right = NULL;
                                  root->left = newNode;
                              }
                              
                              void insertRight(node *root, int item)
                              {
                                  node *newNode = new node;
                                  newNode->val = item;
                                  newNode->left = NULL;
                                  newNode->right = NULL;
                                  root->right = newNode;
                              }
                              ``
                              

                              @ChatGPT 请再给出搜索函数

                              ChatGPTC 1 Reply Last reply
                              0
                              • E eatmelon

                                ChatGPT 说:

                                eatmelon说:

                                ChatGPT 说:

                                eatmelon说:

                                ChatGPT 说:

                                eatmelon说:

                                用C加加实现一个函数Clear,这个函数参数是一个指针,指向一个类型为node的二叉树节点(node类型有三个值,分别代表着这指向左子树,右子树的指针和节点本身的值,当没有左子树和右子树时,指针指向null),这个函数可以将参数及其子树的值全部设为零,该函数不得出现异常

                                ,即使参数指向null也要正常运行。

                                void Clear(node *root)
                                {
                                    if(root == NULL)
                                        return;
                                    Clear(root->left);
                                    Clear(root->right);
                                    root->val = 0;
                                    root->left = NULL;
                                    root->right = NULL;
                                }
                                

                                请再给出node的定义

                                :

                                struct node
                                {
                                    int val;
                                    node *left;
                                    node *right;
                                };
                                ``
                                

                                请再给出插入左子树,右子树的函数

                                void insertLeft(node *root, int item)
                                {
                                    node *newNode = new node;
                                    newNode->val = item;
                                    newNode->left = NULL;
                                    newNode->right = NULL;
                                    root->left = newNode;
                                }
                                
                                void insertRight(node *root, int item)
                                {
                                    node *newNode = new node;
                                    newNode->val = item;
                                    newNode->left = NULL;
                                    newNode->right = NULL;
                                    root->right = newNode;
                                }
                                ``
                                

                                @ChatGPT 请再给出搜索函数

                                ChatGPTC Offline
                                ChatGPTC Offline
                                ChatGPT
                                wrote on last edited by
                                #1495

                                eatmelon说:

                                ChatGPT 说:

                                eatmelon说:

                                ChatGPT 说:

                                eatmelon说:

                                ChatGPT 说:

                                eatmelon说:

                                用C加加实现一个函数Clear,这个函数参数是一个指针,指向一个类型为node的二叉树节点(node类型有三个值,分别代表着这指向左子树,右子树的指针和节点本身的值,当没有左子树和右子树时,指针指向null),这个函数可以将参数及其子树的值全部设为零,该函数不得出现异常

                                ,即使参数指向null也要正常运行。

                                void Clear(node *root)
                                {
                                    if(root == NULL)
                                        return;
                                    Clear(root->left);
                                    Clear(root->right);
                                    root->val = 0;
                                    root->left = NULL;
                                    root->right = NULL;
                                }
                                

                                请再给出node的定义

                                :

                                struct node
                                {
                                    int val;
                                    node *left;
                                    node *right;
                                };
                                ``
                                

                                请再给出插入左子树,右子树的函数

                                void insertLeft(node *root, int item)
                                {
                                    node *newNode = new node;
                                    newNode->val = item;
                                    newNode->left = NULL;
                                    newNode->right = NULL;
                                    root->left = newNode;
                                }
                                
                                void insertRight(node *root, int item)
                                {
                                    node *newNode = new node;
                                    newNode->val = item;
                                    newNode->left = NULL;
                                    newNode->right = NULL;
                                    root->right = newNode;
                                }
                                ``
                                

                                请再给出搜索函数

                                帖子内容中 @ChatGPT(注意前后空格,发帖后名称变色才行)。必须@才会回答

                                1 Reply Last reply
                                0
                                • ChatGPTC ChatGPT

                                  eatmelon说:

                                  ChatGPT 说:

                                  eatmelon说:

                                  ChatGPT 说:

                                  eatmelon说:

                                  用C加加实现一个函数Clear,这个函数参数是一个指针,指向一个类型为node的二叉树节点(node类型有三个值,分别代表着这指向左子树,右子树的指针和节点本身的值,当没有左子树和右子树时,指针指向null),这个函数可以将参数及其子树的值全部设为零,该函数不得出现异常

                                  ,即使参数指向null也要正常运行。

                                  void Clear(node *root)
                                  {
                                      if(root == NULL)
                                          return;
                                      Clear(root->left);
                                      Clear(root->right);
                                      root->val = 0;
                                      root->left = NULL;
                                      root->right = NULL;
                                  }
                                  

                                  请再给出node的定义

                                  :

                                  struct node
                                  {
                                      int val;
                                      node *left;
                                      node *right;
                                  };
                                  ``
                                  

                                  请再给出插入左子树,右子树的函数

                                  void insertLeft(node *root, int item)
                                  {
                                      node *newNode = new node;
                                      newNode->val = item;
                                      newNode->left = NULL;
                                      newNode->right = NULL;
                                      root->left = newNode;
                                  }
                                  
                                  void insertRight(node *root, int item)
                                  {
                                      node *newNode = new node;
                                      newNode->val = item;
                                      newNode->left = NULL;
                                      newNode->right = NULL;
                                      root->right = newNode;
                                  }
                                  ``
                                  E Offline
                                  E Offline
                                  eatmelon
                                  🍌
                                  wrote on last edited by
                                  #1496

                                  ChatGPT 说:

                                  eatmelon说:

                                  ChatGPT 说:

                                  eatmelon说:

                                  ChatGPT 说:

                                  eatmelon说:

                                  用C加加实现一个函数Clear,这个函数参数是一个指针,指向一个类型为node的二叉树节点(node类型有三个值,分别代表着这指向左子树,右子树的指针和节点本身的值,当没有左子树和右子树时,指针指向null),这个函数可以将参数及其子树的值全部设为零,该函数不得出现异常

                                  ,即使参数指向null也要正常运行。

                                  void Clear(node *root)
                                  {
                                      if(root == NULL)
                                          return;
                                      Clear(root->left);
                                      Clear(root->right);
                                      root->val = 0;
                                      root->left = NULL;
                                      root->right = NULL;
                                  }
                                  

                                  请再给出node的定义

                                  :

                                  struct node
                                  {
                                      int val;
                                      node *left;
                                      node *right;
                                  };
                                  ``
                                  

                                  请再给出插入左子树,右子树的函数

                                  void insertLeft(node *root, int item)
                                  {
                                      node *newNode = new node;
                                      newNode->val = item;
                                      newNode->left = NULL;
                                      newNode->right = NULL;
                                      root->left = newNode;
                                  }
                                  
                                  void insertRight(node *root, int item)
                                  {
                                      node *newNode = new node;
                                      newNode->val = item;
                                      newNode->left = NULL;
                                      newNode->right = NULL;
                                      root->right = newNode;
                                  }
                                  ``
                                  

                                  @ChatGPT
                                  请再给出能搜索二叉树中含有特定值的结点的函数

                                  ChatGPTC 1 Reply Last reply
                                  0
                                  • E eatmelon

                                    ChatGPT 说:

                                    eatmelon说:

                                    ChatGPT 说:

                                    eatmelon说:

                                    ChatGPT 说:

                                    eatmelon说:

                                    用C加加实现一个函数Clear,这个函数参数是一个指针,指向一个类型为node的二叉树节点(node类型有三个值,分别代表着这指向左子树,右子树的指针和节点本身的值,当没有左子树和右子树时,指针指向null),这个函数可以将参数及其子树的值全部设为零,该函数不得出现异常

                                    ,即使参数指向null也要正常运行。

                                    void Clear(node *root)
                                    {
                                        if(root == NULL)
                                            return;
                                        Clear(root->left);
                                        Clear(root->right);
                                        root->val = 0;
                                        root->left = NULL;
                                        root->right = NULL;
                                    }
                                    

                                    请再给出node的定义

                                    :

                                    struct node
                                    {
                                        int val;
                                        node *left;
                                        node *right;
                                    };
                                    ``
                                    

                                    请再给出插入左子树,右子树的函数

                                    void insertLeft(node *root, int item)
                                    {
                                        node *newNode = new node;
                                        newNode->val = item;
                                        newNode->left = NULL;
                                        newNode->right = NULL;
                                        root->left = newNode;
                                    }
                                    
                                    void insertRight(node *root, int item)
                                    {
                                        node *newNode = new node;
                                        newNode->val = item;
                                        newNode->left = NULL;
                                        newNode->right = NULL;
                                        root->right = newNode;
                                    }
                                    ``
                                    

                                    @ChatGPT
                                    请再给出能搜索二叉树中含有特定值的结点的函数

                                    ChatGPTC Offline
                                    ChatGPTC Offline
                                    ChatGPT
                                    wrote on last edited by
                                    #1497

                                    eatmelon说:

                                    ChatGPT 说:

                                    eatmelon说:

                                    ChatGPT 说:

                                    eatmelon说:

                                    ChatGPT 说:

                                    eatmelon说:

                                    用C加加实现一个函数Clear,这个函数参数是一个指针,指向一个类型为node的二叉树节点(node类型有三个值,分别代表着这指向左子树,右子树的指针和节点本身的值,当没有左子树和右子树时,指针指向null),这个函数可以将参数及其子树的值全部设为零,该函数不得出现异常

                                    ,即使参数指向null也要正常运行。

                                    void Clear(node *root)
                                    {
                                        if(root == NULL)
                                            return;
                                        Clear(root->left);
                                        Clear(root->right);
                                        root->val = 0;
                                        root->left = NULL;
                                        root->right = NULL;
                                    }
                                    

                                    请再给出node的定义

                                    :

                                    struct node
                                    {
                                        int val;
                                        node *left;
                                        node *right;
                                    };
                                    ``
                                    

                                    请再给出插入左子树,右子树的函数

                                    void insertLeft(node *root, int item)
                                    {
                                        node *newNode = new node;
                                        newNode->val = item;
                                        newNode->left = NULL;
                                        newNode->right = NULL;
                                        root->left = newNode;
                                    }
                                    
                                    void insertRight(node *root, int item)
                                    {
                                        node *newNode = new node;
                                        newNode->val = item;
                                        newNode->left = NULL;
                                        newNode->right = NULL;
                                        root->right = newNode;
                                    }
                                    ``
                                    

                                    请再给出能搜索二叉树中含有特定值的结点的函数

                                    帖子内容中 @ChatGPT(注意前后空格,发帖后名称变色才行)。必须@才会回答

                                    1 Reply Last reply
                                    0
                                    • E Offline
                                      E Offline
                                      eatmelon
                                      🍌
                                      wrote on last edited by
                                      #1498

                                      @ChatGPT 请基于红黑树技术写出一段搜索树,语言为C++,不得使用stl标准库

                                      ChatGPTC 1 Reply Last reply
                                      0
                                      • E eatmelon

                                        @ChatGPT 请基于红黑树技术写出一段搜索树,语言为C++,不得使用stl标准库

                                        ChatGPTC Offline
                                        ChatGPTC Offline
                                        ChatGPT
                                        wrote on last edited by
                                        #1499

                                        eatmelon说:

                                        请基于红黑树技术写出一段搜索树,语言为C++,不得使用stl标准库

                                        #include 
                                        #include 
                                        
                                        //红黑树节点结构定义
                                        struct Node
                                        {
                                            int data;
                                            int color;
                                            Node* left;
                                            Node* right;
                                            Node* parent;
                                        };
                                        
                                        //红黑树类定义
                                        class RBTree
                                        {
                                        private:
                                            Node* root;
                                        
                                        public:
                                            RBTree();
                                            ~RBTree();
                                            void insert(Node* node);
                                            void deleteNode(Node* node);
                                            Node* search(int data);
                                            void leftRotate(Node* node);
                                            void rightRotate(Node* node);
                                            void insertFixUp(Node* node);
                                            void deleteFixUp(Node* node);
                                        };
                                        
                                        //构造函数
                                        RBTree::RBTree()
                                        {
                                            root = NULL;
                                        }
                                        
                                        //析构函数
                                        RBTree::~RBTree()
                                        {
                                            delete root;
                                            root = NULL;
                                        }
                                        
                                        //搜索函数
                                        Node* RBTree::search(int data)
                                        {
                                            Node* current = root;
                                        
                                            while (current != NULL && data != current->data)
                                            {
                                                if (data data)
                                                    current = current->left;
                                                else
                                                    current = current->right;
                                            }
                                        
                                            return current;
                                        }
                                        
                                        //插入函数
                                        void RBTree::insert(Node* node)
                                        {
                                            Node* current = root;
                                            Node* parent = NULL;
                                        
                                            while (current != NULL)
                                            {
                                                parent = current;
                                                if (node->data data)
                                                    current = current->left;
                                                else
                                                    current = current->right;
                                            }
                                        
                                            node->parent = parent;
                                        
                                            if (parent == NULL)
                                                root = node;
                                            else if (node->data data)
                                                parent->left = node;
                                            else
                                                parent->right = node;
                                        
                                            node->left = NULL;
                                            node->right = NULL;
                                            node->color = 0;
                                        
                                            insertFixUp(node);
                                        }
                                        
                                        //左旋函数
                                        void RBTree::leftRotate(Node* node)
                                        {
                                            Node* right = node->right;
                                            node->right = right->left;
                                        
                                            if (right->left != NULL)
                                                right->left->parent = node;
                                        
                                            right->parent = node->parent;
                                        
                                            if (node->parent == NULL)
                                                root = right;
                                            else if (node == node->parent->left)
                                                node->parent->left = right;
                                            else
                                                node->parent->right = right;
                                        
                                            right->left = node;
                                            node->parent = right;
                                        }
                                        
                                        //右旋函数
                                        void RBTree::rightRotate(Node* node)
                                        {
                                            Node* left = node->left;
                                            node->left = left->right;
                                        
                                            if (left->right != NULL)
                                                left->right->parent = node;
                                        
                                            left->parent = node->parent;
                                        
                                            if (node->parent == NULL)
                                                root = left;
                                            else if (node == node->parent->left)
                                                node->parent->left = left;
                                            else
                                                node->parent->right = left;
                                        
                                            left->right = node;
                                            node->parent = left;
                                        }
                                        
                                        //插入修复函数
                                        void RBTree::insertFixUp(Node* node)
                                        {
                                            Node* parent = NULL;
                                            Node* grandparent = NULL;
                                        
                                            while ((node->parent != NULL) && (node->parent->color == 0))
                                            {
                                                parent = node->parent;
                                                grandparent = parent->parent;
                                        
                                                if (parent == grandparent->left)
                                                {
                                                    Node* uncle = grandparent->right;
                                        
                                                    if (uncle != NULL && uncle->color == 0)
                                                    {
                                                        grandparent->color = 0;
                                                        parent->color = 1;
                                                        uncle->color = 1;
                                                        node = grandparent;
                                                    }
                                                    else
                                                    {
                                                        if (node == parent->right)
                                                        {
                                                            node = parent;
                                                            leftRotate(node);
                                                        }
                                        
                                                        parent = node->parent;
                                                        grandparent = parent->parent;
                                                        grandparent->color = 0;
                                                        parent->color = 1;
                                                        rightRotate(grandparent);
                                                    }
                                                }
                                                else
                                                {
                                                    Node* uncle = grandparent->left;
                                        
                                                    if (uncle != NULL && uncle->color == 0)
                                                    {
                                                        grandparent->color = 0;
                                                        parent->color = 1;
                                                        uncle->color = 1;
                                                        node = grandparent;
                                                    }
                                                    else
                                                    {
                                                        if (node == parent->left)
                                                        {
                                                            node = parent;
                                                            rightRotate(node);
                                                        }
                                        
                                                        parent = node->parent;
                                                        grandparent = parent->parent;
                                                        grandparent->color = 0;
                                                        parent->color = 1;
                                                        leftRotate(grandparent);
                                                    }
                                                }
                                            }
                                            root->color = 1;
                                        }
                                        
                                        //删除函数
                                        void RBTree::deleteNode(Node* node)
                                        {
                                            //定义临时节点
                                            Node* temp = node;
                                            Node* child;
                                            int temp_color = temp->color;
                                        
                                            if (node->left == NULL)
                                            {
                                                child = node->right;
                                                transplant(node, node->right);
                                            }
                                            else if (node->right == NULL)
                                            {
                                                child = node->left;
                                                transplant(node, node->left);
                                            }
                                            else
                                            {
                                                temp = minimum(node->right);
                                                temp_color = temp->color;
                                                child = temp->right;
                                                if (temp->parent == node)
                                                {
                                                    child->parent = temp;
                                                }
                                                else
                                                {
                                                    transplant(temp, temp->right);
                                                    temp->right = node->right;
                                                    temp->right->parent = temp;
                                                }
                                                transplant(node, temp);
                                                temp->left = node->left;
                                                temp->left->parent = temp;
                                                temp->color = node->color;
                                            }
                                            if (temp_color == 1)
                                            {
                                                deleteFixUp(child);
                                            }
                                        }
                                        
                                        //删除修复函数
                                        void RBTree::deleteFixUp(Node* node)
                                        {
                                            Node *parent, *sibling;
                                        
                                            while ((node != root) && (node->color == 1))
                                            {
                                                parent = node->parent;
                                                if (node == parent->left)
                                                {
                                                    sibling = parent->right;
                                                    if (sibling->color == 0)
                                                    {
                                                        sibling->color = 1;
                                                        parent->color = 0;
                                                        leftRotate(parent);
                                                        sibling = parent->right;
                                                    }
                                                    if ((sibling->left->color == 1) && (sibling->right->color == 1))
                                                    {
                                                        sibling->color = 0;
                                                        node = parent;
                                                    }
                                                    else
                                                    {
                                                        if (sibling->right->color == 1)
                                                        {
                                                            sibling->left->color = 1;
                                                            sibling->color = 0;
                                                            rightRotate(sibling);
                                                            sibling = parent->right;
                                                        }
                                                        sibling->color = parent->color;
                                                        parent->color = 1;
                                                        sibling->right->color = 1;
                                                        leftRotate(parent);
                                                        node = root;
                                                    }
                                                }
                                                else
                                                {
                                                    sibling = parent->left;
                                                    if (sibling->color == 0)
                                                    {
                                                        sibling->color = 1;
                                                        parent->color = 0;
                                                        rightRotate(parent);
                                                        sibling = parent->left;
                                                    }
                                                    if ((sibling->left->color == 1) && (sibling->right->color == 1))
                                                    {
                                                        sibling->color = 0;
                                                        node = parent;
                                                    }
                                                    else
                                                    {
                                                        if (sibling->left->color == 1)
                                                        {
                                                            sibling->right->color = 1;
                                                            sibling->color = 0;
                                                            leftRotate(sibling);
                                                            sibling = parent->left;
                                                        }
                                                        sibling->color = parent->color;
                                                        parent->color = 1;
                                                        sibling->left->color = 1;
                                                        rightRotate(parent);
                                                        node = root;
                                                    }
                                                }
                                            }
                                            node->color = 1;
                                        }
                                        

                                        帖子内容中 @ChatGPT(注意前后空格,发帖后名称变色才行)。必须@才会回答

                                        E 2 Replies Last reply
                                        0
                                        • ChatGPTC ChatGPT

                                          eatmelon说:

                                          请基于红黑树技术写出一段搜索树,语言为C++,不得使用stl标准库

                                          #include 
                                          #include 
                                          
                                          //红黑树节点结构定义
                                          struct Node
                                          {
                                              int data;
                                              int color;
                                              Node* left;
                                              Node* right;
                                              Node* parent;
                                          };
                                          
                                          //红黑树类定义
                                          class RBTree
                                          {
                                          private:
                                              Node* root;
                                          
                                          public:
                                              RBTree();
                                              ~RBTree();
                                              void insert(Node* node);
                                              void deleteNode(Node* node);
                                              Node* search(int data);
                                              void leftRotate(Node* node);
                                              void rightRotate(Node* node);
                                              void insertFixUp(Node* node);
                                              void deleteFixUp(Node* node);
                                          };
                                          
                                          //构造函数
                                          RBTree::RBTree()
                                          {
                                              root = NULL;
                                          }
                                          
                                          //析构函数
                                          RBTree::~RBTree()
                                          {
                                              delete root;
                                              root = NULL;
                                          }
                                          
                                          //搜索函数
                                          Node* RBTree::search(int data)
                                          {
                                              Node* current = root;
                                          
                                              while (current != NULL && data != current->data)
                                              {
                                                  if (data data)
                                                      current = current->left;
                                                  else
                                                      current = current->right;
                                              }
                                          
                                              return current;
                                          }
                                          
                                          //插入函数
                                          void RBTree::insert(Node* node)
                                          {
                                              Node* current = root;
                                              Node* parent = NULL;
                                          
                                              while (current != NULL)
                                              {
                                                  parent = current;
                                                  if (node->data data)
                                                      current = current->left;
                                                  else
                                                      current = current->right;
                                              }
                                          
                                              node->parent = parent;
                                          
                                              if (parent == NULL)
                                                  root = node;
                                              else if (node->data data)
                                                  parent->left = node;
                                              else
                                                  parent->right = node;
                                          
                                              node->left = NULL;
                                              node->right = NULL;
                                              node->color = 0;
                                          
                                              insertFixUp(node);
                                          }
                                          
                                          //左旋函数
                                          void RBTree::leftRotate(Node* node)
                                          {
                                              Node* right = node->right;
                                              node->right = right->left;
                                          
                                              if (right->left != NULL)
                                                  right->left->parent = node;
                                          
                                              right->parent = node->parent;
                                          
                                              if (node->parent == NULL)
                                                  root = right;
                                              else if (node == node->parent->left)
                                                  node->parent->left = right;
                                              else
                                                  node->parent->right = right;
                                          
                                              right->left = node;
                                              node->parent = right;
                                          }
                                          
                                          //右旋函数
                                          void RBTree::rightRotate(Node* node)
                                          {
                                              Node* left = node->left;
                                              node->left = left->right;
                                          
                                              if (left->right != NULL)
                                                  left->right->parent = node;
                                          
                                              left->parent = node->parent;
                                          
                                              if (node->parent == NULL)
                                                  root = left;
                                              else if (node == node->parent->left)
                                                  node->parent->left = left;
                                              else
                                                  node->parent->right = left;
                                          
                                              left->right = node;
                                              node->parent = left;
                                          }
                                          
                                          //插入修复函数
                                          void RBTree::insertFixUp(Node* node)
                                          {
                                              Node* parent = NULL;
                                              Node* grandparent = NULL;
                                          
                                              while ((node->parent != NULL) && (node->parent->color == 0))
                                              {
                                                  parent = node->parent;
                                                  grandparent = parent->parent;
                                          
                                                  if (parent == grandparent->left)
                                                  {
                                                      Node* uncle = grandparent->right;
                                          
                                                      if (uncle != NULL && uncle->color == 0)
                                                      {
                                                          grandparent->color = 0;
                                                          parent->color = 1;
                                                          uncle->color = 1;
                                                          node = grandparent;
                                                      }
                                                      else
                                                      {
                                                          if (node == parent->right)
                                                          {
                                                              node = parent;
                                                              leftRotate(node);
                                                          }
                                          
                                                          parent = node->parent;
                                                          grandparent = parent->parent;
                                                          grandparent->color = 0;
                                                          parent->color = 1;
                                                          rightRotate(grandparent);
                                                      }
                                                  }
                                                  else
                                                  {
                                                      Node* uncle = grandparent->left;
                                          
                                                      if (uncle != NULL && uncle->color == 0)
                                                      {
                                                          grandparent->color = 0;
                                                          parent->color = 1;
                                                          uncle->color = 1;
                                                          node = grandparent;
                                                      }
                                                      else
                                                      {
                                                          if (node == parent->left)
                                                          {
                                                              node = parent;
                                                              rightRotate(node);
                                                          }
                                          
                                                          parent = node->parent;
                                                          grandparent = parent->parent;
                                                          grandparent->color = 0;
                                                          parent->color = 1;
                                                          leftRotate(grandparent);
                                                      }
                                                  }
                                              }
                                              root->color = 1;
                                          }
                                          
                                          //删除函数
                                          void RBTree::deleteNode(Node* node)
                                          {
                                              //定义临时节点
                                              Node* temp = node;
                                              Node* child;
                                              int temp_color = temp->color;
                                          
                                              if (node->left == NULL)
                                              {
                                                  child = node->right;
                                                  transplant(node, node->right);
                                              }
                                              else if (node->right == NULL)
                                              {
                                                  child = node->left;
                                                  transplant(node, node->left);
                                              }
                                              else
                                              {
                                                  temp = minimum(node->right);
                                                  temp_color = temp->color;
                                                  child = temp->right;
                                                  if (temp->parent == node)
                                                  {
                                                      child->parent = temp;
                                                  }
                                                  else
                                                  {
                                                      transplant(temp, temp->right);
                                                      temp->right = node->right;
                                                      temp->right->parent = temp;
                                                  }
                                                  transplant(node, temp);
                                                  temp->left = node->left;
                                                  temp->left->parent = temp;
                                                  temp->color = node->color;
                                              }
                                              if (temp_color == 1)
                                              {
                                                  deleteFixUp(child);
                                              }
                                          }
                                          
                                          //删除修复函数
                                          void RBTree::deleteFixUp(Node* node)
                                          {
                                              Node *parent, *sibling;
                                          
                                              while ((node != root) && (node->color == 1))
                                              {
                                                  parent = node->parent;
                                                  if (node == parent->left)
                                                  {
                                                      sibling = parent->right;
                                                      if (sibling->color == 0)
                                                      {
                                                          sibling->color = 1;
                                                          parent->color = 0;
                                                          leftRotate(parent);
                                                          sibling = parent->right;
                                                      }
                                                      if ((sibling->left->color == 1) && (sibling->right->color == 1))
                                                      {
                                                          sibling->color = 0;
                                                          node = parent;
                                                      }
                                                      else
                                                      {
                                                          if (sibling->right->color == 1)
                                                          {
                                                              sibling->left->color = 1;
                                                              sibling->color = 0;
                                                              rightRotate(sibling);
                                                              sibling = parent->right;
                                                          }
                                                          sibling->color = parent->color;
                                                          parent->color = 1;
                                                          sibling->right->color = 1;
                                                          leftRotate(parent);
                                                          node = root;
                                                      }
                                                  }
                                                  else
                                                  {
                                                      sibling = parent->left;
                                                      if (sibling->color == 0)
                                                      {
                                                          sibling->color = 1;
                                                          parent->color = 0;
                                                          rightRotate(parent);
                                                          sibling = parent->left;
                                                      }
                                                      if ((sibling->left->color == 1) && (sibling->right->color == 1))
                                                      {
                                                          sibling->color = 0;
                                                          node = parent;
                                                      }
                                                      else
                                                      {
                                                          if (sibling->left->color == 1)
                                                          {
                                                              sibling->right->color = 1;
                                                              sibling->color = 0;
                                                              leftRotate(sibling);
                                                              sibling = parent->left;
                                                          }
                                                          sibling->color = parent->color;
                                                          parent->color = 1;
                                                          sibling->left->color = 1;
                                                          rightRotate(parent);
                                                          node = root;
                                                      }
                                                  }
                                              }
                                              node->color = 1;
                                          }
                                          
                                          E Offline
                                          E Offline
                                          eatmelon
                                          🍌
                                          wrote on last edited by eatmelon
                                          #1500

                                          ChatGPT 说:

                                          eatmelon说:

                                          请基于红黑树技术写出一段搜索树,语言为C++,不得使用stl标准库

                                          #include 
                                          #include 
                                          
                                          //红黑树节点结构定义
                                          struct Node
                                          {
                                              int data;
                                              int color;
                                              Node* left;
                                              Node* right;
                                              Node* parent;
                                          };
                                          
                                          //红黑树类定义
                                          class RBTree
                                          {
                                          private:
                                              Node* root;
                                          
                                          public:
                                              RBTree();
                                              ~RBTree();
                                              void insert(Node* node);
                                              void deleteNode(Node* node);
                                              Node* search(int data);
                                              void leftRotate(Node* node);
                                              void rightRotate(Node* node);
                                              void insertFixUp(Node* node);
                                              void deleteFixUp(Node* node);
                                          };
                                          
                                          //构造函数
                                          RBTree::RBTree()
                                          {
                                              root = NULL;
                                          }
                                          
                                          //析构函数
                                          RBTree::~RBTree()
                                          {
                                              delete root;
                                              root = NULL;
                                          }
                                          
                                          //搜索函数
                                          Node* RBTree::search(int data)
                                          {
                                              Node* current = root;
                                          
                                              while (current != NULL && data != current->data)
                                              {
                                                  if (data data)
                                                      current = current->left;
                                                  else
                                                      current = current->right;
                                              }
                                          
                                              return current;
                                          }
                                          
                                          //插入函数
                                          void RBTree::insert(Node* node)
                                          {
                                              Node* current = root;
                                              Node* parent = NULL;
                                          
                                              while (current != NULL)
                                              {
                                                  parent = current;
                                                  if (node->data data)
                                                      current = current->left;
                                                  else
                                                      current = current->right;
                                              }
                                          
                                              node->parent = parent;
                                          
                                              if (parent == NULL)
                                                  root = node;
                                              else if (node->data data)
                                                  parent->left = node;
                                              else
                                                  parent->right = node;
                                          
                                              node->left = NULL;
                                              node->right = NULL;
                                              node->color = 0;
                                          
                                              insertFixUp(node);
                                          }
                                          
                                          //左旋函数
                                          void RBTree::leftRotate(Node* node)
                                          {
                                              Node* right = node->right;
                                              node->right = right->left;
                                          
                                              if (right->left != NULL)
                                                  right->left->parent = node;
                                          
                                              right->parent = node->parent;
                                          
                                              if (node->parent == NULL)
                                                  root = right;
                                              else if (node == node->parent->left)
                                                  node->parent->left = right;
                                              else
                                                  node->parent->right = right;
                                          
                                              right->left = node;
                                              node->parent = right;
                                          }
                                          
                                          //右旋函数
                                          void RBTree::rightRotate(Node* node)
                                          {
                                              Node* left = node->left;
                                              node->left = left->right;
                                          
                                              if (left->right != NULL)
                                                  left->right->parent = node;
                                          
                                              left->parent = node->parent;
                                          
                                              if (node->parent == NULL)
                                                  root = left;
                                              else if (node == node->parent->left)
                                                  node->parent->left = left;
                                              else
                                                  node->parent->right = left;
                                          
                                              left->right = node;
                                              node->parent = left;
                                          }
                                          
                                          //插入修复函数
                                          void RBTree::insertFixUp(Node* node)
                                          {
                                              Node* parent = NULL;
                                              Node* grandparent = NULL;
                                          
                                              while ((node->parent != NULL) && (node->parent->color == 0))
                                              {
                                                  parent = node->parent;
                                                  grandparent = parent->parent;
                                          
                                                  if (parent == grandparent->left)
                                                  {
                                                      Node* uncle = grandparent->right;
                                          
                                                      if (uncle != NULL && uncle->color == 0)
                                                      {
                                                          grandparent->color = 0;
                                                          parent->color = 1;
                                                          uncle->color = 1;
                                                          node = grandparent;
                                                      }
                                                      else
                                                      {
                                                          if (node == parent->right)
                                                          {
                                                              node = parent;
                                                              leftRotate(node);
                                                          }
                                          
                                                          parent = node->parent;
                                                          grandparent = parent->parent;
                                                          grandparent->color = 0;
                                                          parent->color = 1;
                                                          rightRotate(grandparent);
                                                      }
                                                  }
                                                  else
                                                  {
                                                      Node* uncle = grandparent->left;
                                          
                                                      if (uncle != NULL && uncle->color == 0)
                                                      {
                                                          grandparent->color = 0;
                                                          parent->color = 1;
                                                          uncle->color = 1;
                                                          node = grandparent;
                                                      }
                                                      else
                                                      {
                                                          if (node == parent->left)
                                                          {
                                                              node = parent;
                                                              rightRotate(node);
                                                          }
                                          
                                                          parent = node->parent;
                                                          grandparent = parent->parent;
                                                          grandparent->color = 0;
                                                          parent->color = 1;
                                                          leftRotate(grandparent);
                                                      }
                                                  }
                                              }
                                              root->color = 1;
                                          }
                                          
                                          //删除函数
                                          void RBTree::deleteNode(Node* node)
                                          {
                                              //定义临时节点
                                              Node* temp = node;
                                              Node* child;
                                              int temp_color = temp->color;
                                          
                                              if (node->left == NULL)
                                              {
                                                  child = node->right;
                                                  transplant(node, node->right);
                                              }
                                              else if (node->right == NULL)
                                              {
                                                  child = node->left;
                                                  transplant(node, node->left);
                                              }
                                              else
                                              {
                                                  temp = minimum(node->right);
                                                  temp_color = temp->color;
                                                  child = temp->right;
                                                  if (temp->parent == node)
                                                  {
                                                      child->parent = temp;
                                                  }
                                                  else
                                                  {
                                                      transplant(temp, temp->right);
                                                      temp->right = node->right;
                                                      temp->right->parent = temp;
                                                  }
                                                  transplant(node, temp);
                                                  temp->left = node->left;
                                                  temp->left->parent = temp;
                                                  temp->color = node->color;
                                              }
                                              if (temp_color == 1)
                                              {
                                                  deleteFixUp(child);
                                              }
                                          }
                                          
                                          //删除修复函数
                                          void RBTree::deleteFixUp(Node* node)
                                          {
                                              Node *parent, *sibling;
                                          
                                              while ((node != root) && (node->color == 1))
                                              {
                                                  parent = node->parent;
                                                  if (node == parent->left)
                                                  {
                                                      sibling = parent->right;
                                                      if (sibling->color == 0)
                                                      {
                                                          sibling->color = 1;
                                                          parent->color = 0;
                                                          leftRotate(parent);
                                                          sibling = parent->right;
                                                      }
                                                      if ((sibling->left->color == 1) && (sibling->right->color == 1))
                                                      {
                                                          sibling->color = 0;
                                                          node = parent;
                                                      }
                                                      else
                                                      {
                                                          if (sibling->right->color == 1)
                                                          {
                                                              sibling->left->color = 1;
                                                              sibling->color = 0;
                                                              rightRotate(sibling);
                                                              sibling = parent->right;
                                                          }
                                                          sibling->color = parent->color;
                                                          parent->color = 1;
                                                          sibling->right->color = 1;
                                                          leftRotate(parent);
                                                          node = root;
                                                      }
                                                  }
                                                  else
                                                  {
                                                      sibling = parent->left;
                                                      if (sibling->color == 0)
                                                      {
                                                          sibling->color = 1;
                                                          parent->color = 0;
                                                          rightRotate(parent);
                                                          sibling = parent->left;
                                                      }
                                                      if ((sibling->left->color == 1) && (sibling->right->color == 1))
                                                      {
                                                          sibling->color = 0;
                                                          node = parent;
                                                      }
                                                      else
                                                      {
                                                          if (sibling->left->color == 1)
                                                          {
                                                              sibling->right->color = 1;
                                                              sibling->color = 0;
                                                              leftRotate(sibling);
                                                              sibling = parent->left;
                                                          }
                                                          sibling->color = parent->color;
                                                          parent->color = 1;
                                                          sibling->left->color = 1;
                                                          rightRotate(parent);
                                                          node = root;
                                                      }
                                                  }
                                              }
                                              node->color = 1;
                                          }
                                          

                                          @ChatGPT 请解释该代码

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