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gao55pan说:
请用fastapi和Vue Admin实现学生信息的管理功能，可以实现增删改查功能，要求目录结构完整，并且给出详细的代码
。
Fastapi代码：
from fastapi import FastAPI from pydantic import BaseModel app = FastAPI() # 定义学生的Model class Student(BaseModel): id: str name: str age: int gender: str # 定义学生的列表 students = [ { "id": "stu_001", "name": "小明", "age": 18, "gender": "male" } ] # 根据id获取学生 @app.get("/student/{id}") def get_student_by_id(id: str): for student in students: if student["id"] == id: return student # 获取所有学生 @app.get("/students") def get_students(): return students # 添加学生 @app.post("/student") def add_student(student: Student): students.append(student.dict()) return student # 修改学生信息 @app.put("/student/{id}") def update_student(id: str, student: Student): for s in students: if s["id"] == id: s.update(student.dict()) return s # 删除学生 @app.delete("/student/{id}") def delete_student(id: str): for i, s in enumerate(students): if s["id"] == id: del students[i] return sVue Admin代码：
编辑 删除 取 消 确 定 export default { data() { return { students: [], dialogVisible: false, genders: [ { value: 'male', label: '男' }, { value: 'female', label: '女' } ], form: { name: '', age: '', gender: '' } } }, methods: { // 获取所有学生 getStudents() { this.$axios.get('http://127.0.0.1:8000/students').then(res => { this.students = res.data }) }, // 编辑学生信息 handleEdit(index, row) { this.dialogVisible = true this.form.name = row.name this.form.age = row.age this.form.gender = row.gender }, // 删除学生 handleDelete(index, row) { this.$axios.delete(`http://127.0.0.1:8000/student/${row.id}`).then(res => { this.students.splice(index, 1) }) }, // 保存学生 saveStudent() { this.$axios.put(`http://127.0.0.1:8000/student/${row.id}`, this.form).then(res => { this.students.splice(index, 1, res.data) }) } }, created() { this.getStudents() } } -
Ss1110说:
C 语言编写一个if-else语句和switch语句编写程序表示90-100为优秀，80-89为良好，60-79为及格，60以下为不及格
if-else语句：
if(score>=90 && score=80 && score=60 && score<=79) printf("及格\n"); else printf("不及格\n");switch语句：
switch(score){ case 90 ... 100: printf("优秀\n"); break; case 80 ... 89: printf("良好\n"); break; case 60 ... 79: printf("及格\n"); break; default: printf("不及格\n"); break; } -
Ss1110说:
C 语言编写一个输入数字并用if-else语句和switch语句编写程序表示90-100为优秀，80-89为良好，60-79为及格，60以下为不及格
// 使用 if-else 语句
#include
int main()
{
int number;
printf("Please input a number: ");
scanf("%d", &number);
if (number >= 90 && number = 80 && number = 60 && number
int main()
{
int number;
printf("Please input a number: ");
scanf("%d", &number);
switch (number / 10)
{
case 10:
case 9:
printf("Excellent\n");
break;
case 8:
printf("Good\n");
break;
case 7:
case 6:
printf("Pass\n");
break;
default:
printf("Failed\n");
break;
}
return 0;
} -
gao55pan说:
-- coding: utf-8 --
import scrapy
class ChinazSpider(scrapy.Spider):
name = 'ChinazSpider'
allowed_domains = ['chinaz.com']
start_urls = ['https://www.chinaz.com/']def parse(self, response): # 获取文章链接 article_urls = response.xpath('//div[@class="listCentent"]/h3/a/@href').extract() # 获取每篇文章内容 for article_url in article_urls: yield scrapy.Request(url=article_url, callback=self.parse_detail) def parse_detail(self, response): # 获取文章标题 title = response.xpath('//div[@class="ph_news"]/h1/text()').extract_first() # 获取文章内容 content = response.xpath('//div[@class="ph_news"]/div[@class="ph_content"]/p/text()').extract() # 把标题和内容作为字典传给item item = { 'title': title, 'content': content } yield item -
gao55pan说:
scrapy遇到这个报错怎么结局 [twisted] CRITICAL: Unhandled error in Deferred:
Scrapy是一个强大的爬虫框架，可以用来抓取网页数据。然而，Scrapy也可能会遇到一些错误，其中一个是[twisted] CRITICAL: Unhandled error in Deferred，这是由于Scrapy出现了一些未处理的错误，导致无法正常工作。
要解决这个问题，首先需要检查Scrapy的日志，以查看是否有任何错误。如果发现了错误，需要查看其详细信息，以确定原因。然后，将查找特定的解决办法，以解决这个问题。
此外，也可以重新安装Scrapy，以确保它运行正常。最后，可以尝试更新Scrapy，以确保它可以正确处理新的功能。
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