本社区终于可以向 @ChatGPT 提问了！

ChatGPT

eatmelon说:

ChatGPT 说：

eatmelon说:

请基于红黑树技术写出一段搜索树，语言为C++，不得使用stl标准库

#include 
#include 

//红黑树节点结构定义
struct Node
{
    int data;
    int color;
    Node* left;
    Node* right;
    Node* parent;
};

//红黑树类定义
class RBTree
{
private:
    Node* root;

public:
    RBTree();
    ~RBTree();
    void insert(Node* node);
    void deleteNode(Node* node);
    Node* search(int data);
    void leftRotate(Node* node);
    void rightRotate(Node* node);
    void insertFixUp(Node* node);
    void deleteFixUp(Node* node);
};

//构造函数
RBTree::RBTree()
{
    root = NULL;
}

//析构函数
RBTree::~RBTree()
{
    delete root;
    root = NULL;
}

//搜索函数
Node* RBTree::search(int data)
{
    Node* current = root;

    while (current != NULL && data != current->data)
    {
        if (data data)
            current = current->left;
        else
            current = current->right;
    }

    return current;
}

//插入函数
void RBTree::insert(Node* node)
{
    Node* current = root;
    Node* parent = NULL;

    while (current != NULL)
    {
        parent = current;
        if (node->data data)
            current = current->left;
        else
            current = current->right;
    }

    node->parent = parent;

    if (parent == NULL)
        root = node;
    else if (node->data data)
        parent->left = node;
    else
        parent->right = node;

    node->left = NULL;
    node->right = NULL;
    node->color = 0;

    insertFixUp(node);
}

//左旋函数
void RBTree::leftRotate(Node* node)
{
    Node* right = node->right;
    node->right = right->left;

    if (right->left != NULL)
        right->left->parent = node;

    right->parent = node->parent;

    if (node->parent == NULL)
        root = right;
    else if (node == node->parent->left)
        node->parent->left = right;
    else
        node->parent->right = right;

    right->left = node;
    node->parent = right;
}

//右旋函数
void RBTree::rightRotate(Node* node)
{
    Node* left = node->left;
    node->left = left->right;

    if (left->right != NULL)
        left->right->parent = node;

    left->parent = node->parent;

    if (node->parent == NULL)
        root = left;
    else if (node == node->parent->left)
        node->parent->left = left;
    else
        node->parent->right = left;

    left->right = node;
    node->parent = left;
}

//插入修复函数
void RBTree::insertFixUp(Node* node)
{
    Node* parent = NULL;
    Node* grandparent = NULL;

    while ((node->parent != NULL) && (node->parent->color == 0))
    {
        parent = node->parent;
        grandparent = parent->parent;

        if (parent == grandparent->left)
        {
            Node* uncle = grandparent->right;

            if (uncle != NULL && uncle->color == 0)
            {
                grandparent->color = 0;
                parent->color = 1;
                uncle->color = 1;
                node = grandparent;
            }
            else
            {
                if (node == parent->right)
                {
                    node = parent;
                    leftRotate(node);
                }

                parent = node->parent;
                grandparent = parent->parent;
                grandparent->color = 0;
                parent->color = 1;
                rightRotate(grandparent);
            }
        }
        else
        {
            Node* uncle = grandparent->left;

            if (uncle != NULL && uncle->color == 0)
            {
                grandparent->color = 0;
                parent->color = 1;
                uncle->color = 1;
                node = grandparent;
            }
            else
            {
                if (node == parent->left)
                {
                    node = parent;
                    rightRotate(node);
                }

                parent = node->parent;
                grandparent = parent->parent;
                grandparent->color = 0;
                parent->color = 1;
                leftRotate(grandparent);
            }
        }
    }
    root->color = 1;
}

//删除函数
void RBTree::deleteNode(Node* node)
{
    //定义临时节点
    Node* temp = node;
    Node* child;
    int temp_color = temp->color;

    if (node->left == NULL)
    {
        child = node->right;
        transplant(node, node->right);
    }
    else if (node->right == NULL)
    {
        child = node->left;
        transplant(node, node->left);
    }
    else
    {
        temp = minimum(node->right);
        temp_color = temp->color;
        child = temp->right;
        if (temp->parent == node)
        {
            child->parent = temp;
        }
        else
        {
            transplant(temp, temp->right);
            temp->right = node->right;
            temp->right->parent = temp;
        }
        transplant(node, temp);
        temp->left = node->left;
        temp->left->parent = temp;
        temp->color = node->color;
    }
    if (temp_color == 1)
    {
        deleteFixUp(child);
    }
}

//删除修复函数
void RBTree::deleteFixUp(Node* node)
{
    Node *parent, *sibling;

    while ((node != root) && (node->color == 1))
    {
        parent = node->parent;
        if (node == parent->left)
        {
            sibling = parent->right;
            if (sibling->color == 0)
            {
                sibling->color = 1;
                parent->color = 0;
                leftRotate(parent);
                sibling = parent->right;
            }
            if ((sibling->left->color == 1) && (sibling->right->color == 1))
            {
                sibling->color = 0;
                node = parent;
            }
            else
            {
                if (sibling->right->color == 1)
                {
                    sibling->left->color = 1;
                    sibling->color = 0;
                    rightRotate(sibling);
                    sibling = parent->right;
                }
                sibling->color = parent->color;
                parent->color = 1;
                sibling->right->color = 1;
                leftRotate(parent);
                node = root;
            }
        }
        else
        {
            sibling = parent->left;
            if (sibling->color == 0)
            {
                sibling->color = 1;
                parent->color = 0;
                rightRotate(parent);
                sibling = parent->left;
            }
            if ((sibling->left->color == 1) && (sibling->right->color == 1))
            {
                sibling->color = 0;
                node = parent;
            }
            else
            {
                if (sibling->left->color == 1)
                {
                    sibling->right->color = 1;
                    sibling->color = 0;
                    leftRotate(sibling);
                    sibling = parent->left;
                }
                sibling->color = parent->color;
                parent->color = 1;
                sibling->left->color = 1;
                rightRotate(parent);
                node = root;
            }
        }
    }
    node->color = 1;
}

请解释该代码

哎呀, ChatGPT 出问题了, 站长快来修复一下~ @malaohu

eatmelon

ChatGPT 说：

eatmelon说:

请基于红黑树技术写出一段搜索树，语言为C++，不得使用stl标准库

#include 
#include 

//红黑树节点结构定义
struct Node
{
    int data;
    int color;
    Node* left;
    Node* right;
    Node* parent;
};

//红黑树类定义
class RBTree
{
private:
    Node* root;

public:
    RBTree();
    ~RBTree();
    void insert(Node* node);
    void deleteNode(Node* node);
    Node* search(int data);
    void leftRotate(Node* node);
    void rightRotate(Node* node);
    void insertFixUp(Node* node);
    void deleteFixUp(Node* node);
};

//构造函数
RBTree::RBTree()
{
    root = NULL;
}

//析构函数
RBTree::~RBTree()
{
    delete root;
    root = NULL;
}

//搜索函数
Node* RBTree::search(int data)
{
    Node* current = root;

    while (current != NULL && data != current->data)
    {
        if (data data)
            current = current->left;
        else
            current = current->right;
    }

    return current;
}

//插入函数
void RBTree::insert(Node* node)
{
    Node* current = root;
    Node* parent = NULL;

    while (current != NULL)
    {
        parent = current;
        if (node->data data)
            current = current->left;
        else
            current = current->right;
    }

    node->parent = parent;

    if (parent == NULL)
        root = node;
    else if (node->data data)
        parent->left = node;
    else
        parent->right = node;

    node->left = NULL;
    node->right = NULL;
    node->color = 0;

    insertFixUp(node);
}

//左旋函数
void RBTree::leftRotate(Node* node)
{
    Node* right = node->right;
    node->right = right->left;

    if (right->left != NULL)
        right->left->parent = node;

    right->parent = node->parent;

    if (node->parent == NULL)
        root = right;
    else if (node == node->parent->left)
        node->parent->left = right;
    else
        node->parent->right = right;

    right->left = node;
    node->parent = right;
}

//右旋函数
void RBTree::rightRotate(Node* node)
{
    Node* left = node->left;
    node->left = left->right;

    if (left->right != NULL)
        left->right->parent = node;

    left->parent = node->parent;

    if (node->parent == NULL)
        root = left;
    else if (node == node->parent->left)
        node->parent->left = left;
    else
        node->parent->right = left;

    left->right = node;
    node->parent = left;
}

//插入修复函数
void RBTree::insertFixUp(Node* node)
{
    Node* parent = NULL;
    Node* grandparent = NULL;

    while ((node->parent != NULL) && (node->parent->color == 0))
    {
        parent = node->parent;
        grandparent = parent->parent;

        if (parent == grandparent->left)
        {
            Node* uncle = grandparent->right;

            if (uncle != NULL && uncle->color == 0)
            {
                grandparent->color = 0;
                parent->color = 1;
                uncle->color = 1;
                node = grandparent;
            }
            else
            {
                if (node == parent->right)
                {
                    node = parent;
                    leftRotate(node);
                }

                parent = node->parent;
                grandparent = parent->parent;
                grandparent->color = 0;
                parent->color = 1;
                rightRotate(grandparent);
            }
        }
        else
        {
            Node* uncle = grandparent->left;

            if (uncle != NULL && uncle->color == 0)
            {
                grandparent->color = 0;
                parent->color = 1;
                uncle->color = 1;
                node = grandparent;
            }
            else
            {
                if (node == parent->left)
                {
                    node = parent;
                    rightRotate(node);
                }

                parent = node->parent;
                grandparent = parent->parent;
                grandparent->color = 0;
                parent->color = 1;
                leftRotate(grandparent);
            }
        }
    }
    root->color = 1;
}

//删除函数
void RBTree::deleteNode(Node* node)
{
    //定义临时节点
    Node* temp = node;
    Node* child;
    int temp_color = temp->color;

    if (node->left == NULL)
    {
        child = node->right;
        transplant(node, node->right);
    }
    else if (node->right == NULL)
    {
        child = node->left;
        transplant(node, node->left);
    }
    else
    {
        temp = minimum(node->right);
        temp_color = temp->color;
        child = temp->right;
        if (temp->parent == node)
        {
            child->parent = temp;
        }
        else
        {
            transplant(temp, temp->right);
            temp->right = node->right;
            temp->right->parent = temp;
        }
        transplant(node, temp);
        temp->left = node->left;
        temp->left->parent = temp;
        temp->color = node->color;
    }
    if (temp_color == 1)
    {
        deleteFixUp(child);
    }
}

//删除修复函数
void RBTree::deleteFixUp(Node* node)
{
    Node *parent, *sibling;

    while ((node != root) && (node->color == 1))
    {
        parent = node->parent;
        if (node == parent->left)
        {
            sibling = parent->right;
            if (sibling->color == 0)
            {
                sibling->color = 1;
                parent->color = 0;
                leftRotate(parent);
                sibling = parent->right;
            }
            if ((sibling->left->color == 1) && (sibling->right->color == 1))
            {
                sibling->color = 0;
                node = parent;
            }
            else
            {
                if (sibling->right->color == 1)
                {
                    sibling->left->color = 1;
                    sibling->color = 0;
                    rightRotate(sibling);
                    sibling = parent->right;
                }
                sibling->color = parent->color;
                parent->color = 1;
                sibling->right->color = 1;
                leftRotate(parent);
                node = root;
            }
        }
        else
        {
            sibling = parent->left;
            if (sibling->color == 0)
            {
                sibling->color = 1;
                parent->color = 0;
                rightRotate(parent);
                sibling = parent->left;
            }
            if ((sibling->left->color == 1) && (sibling->right->color == 1))
            {
                sibling->color = 0;
                node = parent;
            }
            else
            {
                if (sibling->left->color == 1)
                {
                    sibling->right->color = 1;
                    sibling->color = 0;
                    leftRotate(sibling);
                    sibling = parent->left;
                }
                sibling->color = parent->color;
                parent->color = 1;
                sibling->left->color = 1;
                rightRotate(parent);
                node = root;
            }
        }
    }
    node->color = 1;
}

@ChatGPT 请详尽的解释该代码

ChatGPT

eatmelon说:

ChatGPT 说：

eatmelon说:

请基于红黑树技术写出一段搜索树，语言为C++，不得使用stl标准库

#include 
#include 

//红黑树节点结构定义
struct Node
{
    int data;
    int color;
    Node* left;
    Node* right;
    Node* parent;
};

//红黑树类定义
class RBTree
{
private:
    Node* root;

public:
    RBTree();
    ~RBTree();
    void insert(Node* node);
    void deleteNode(Node* node);
    Node* search(int data);
    void leftRotate(Node* node);
    void rightRotate(Node* node);
    void insertFixUp(Node* node);
    void deleteFixUp(Node* node);
};

//构造函数
RBTree::RBTree()
{
    root = NULL;
}

//析构函数
RBTree::~RBTree()
{
    delete root;
    root = NULL;
}

//搜索函数
Node* RBTree::search(int data)
{
    Node* current = root;

    while (current != NULL && data != current->data)
    {
        if (data data)
            current = current->left;
        else
            current = current->right;
    }

    return current;
}

//插入函数
void RBTree::insert(Node* node)
{
    Node* current = root;
    Node* parent = NULL;

    while (current != NULL)
    {
        parent = current;
        if (node->data data)
            current = current->left;
        else
            current = current->right;
    }

    node->parent = parent;

    if (parent == NULL)
        root = node;
    else if (node->data data)
        parent->left = node;
    else
        parent->right = node;

    node->left = NULL;
    node->right = NULL;
    node->color = 0;

    insertFixUp(node);
}

//左旋函数
void RBTree::leftRotate(Node* node)
{
    Node* right = node->right;
    node->right = right->left;

    if (right->left != NULL)
        right->left->parent = node;

    right->parent = node->parent;

    if (node->parent == NULL)
        root = right;
    else if (node == node->parent->left)
        node->parent->left = right;
    else
        node->parent->right = right;

    right->left = node;
    node->parent = right;
}

//右旋函数
void RBTree::rightRotate(Node* node)
{
    Node* left = node->left;
    node->left = left->right;

    if (left->right != NULL)
        left->right->parent = node;

    left->parent = node->parent;

    if (node->parent == NULL)
        root = left;
    else if (node == node->parent->left)
        node->parent->left = left;
    else
        node->parent->right = left;

    left->right = node;
    node->parent = left;
}

//插入修复函数
void RBTree::insertFixUp(Node* node)
{
    Node* parent = NULL;
    Node* grandparent = NULL;

    while ((node->parent != NULL) && (node->parent->color == 0))
    {
        parent = node->parent;
        grandparent = parent->parent;

        if (parent == grandparent->left)
        {
            Node* uncle = grandparent->right;

            if (uncle != NULL && uncle->color == 0)
            {
                grandparent->color = 0;
                parent->color = 1;
                uncle->color = 1;
                node = grandparent;
            }
            else
            {
                if (node == parent->right)
                {
                    node = parent;
                    leftRotate(node);
                }

                parent = node->parent;
                grandparent = parent->parent;
                grandparent->color = 0;
                parent->color = 1;
                rightRotate(grandparent);
            }
        }
        else
        {
            Node* uncle = grandparent->left;

            if (uncle != NULL && uncle->color == 0)
            {
                grandparent->color = 0;
                parent->color = 1;
                uncle->color = 1;
                node = grandparent;
            }
            else
            {
                if (node == parent->left)
                {
                    node = parent;
                    rightRotate(node);
                }

                parent = node->parent;
                grandparent = parent->parent;
                grandparent->color = 0;
                parent->color = 1;
                leftRotate(grandparent);
            }
        }
    }
    root->color = 1;
}

//删除函数
void RBTree::deleteNode(Node* node)
{
    //定义临时节点
    Node* temp = node;
    Node* child;
    int temp_color = temp->color;

    if (node->left == NULL)
    {
        child = node->right;
        transplant(node, node->right);
    }
    else if (node->right == NULL)
    {
        child = node->left;
        transplant(node, node->left);
    }
    else
    {
        temp = minimum(node->right);
        temp_color = temp->color;
        child = temp->right;
        if (temp->parent == node)
        {
            child->parent = temp;
        }
        else
        {
            transplant(temp, temp->right);
            temp->right = node->right;
            temp->right->parent = temp;
        }
        transplant(node, temp);
        temp->left = node->left;
        temp->left->parent = temp;
        temp->color = node->color;
    }
    if (temp_color == 1)
    {
        deleteFixUp(child);
    }
}

//删除修复函数
void RBTree::deleteFixUp(Node* node)
{
    Node *parent, *sibling;

    while ((node != root) && (node->color == 1))
    {
        parent = node->parent;
        if (node == parent->left)
        {
            sibling = parent->right;
            if (sibling->color == 0)
            {
                sibling->color = 1;
                parent->color = 0;
                leftRotate(parent);
                sibling = parent->right;
            }
            if ((sibling->left->color == 1) && (sibling->right->color == 1))
            {
                sibling->color = 0;
                node = parent;
            }
            else
            {
                if (sibling->right->color == 1)
                {
                    sibling->left->color = 1;
                    sibling->color = 0;
                    rightRotate(sibling);
                    sibling = parent->right;
                }
                sibling->color = parent->color;
                parent->color = 1;
                sibling->right->color = 1;
                leftRotate(parent);
                node = root;
            }
        }
        else
        {
            sibling = parent->left;
            if (sibling->color == 0)
            {
                sibling->color = 1;
                parent->color = 0;
                rightRotate(parent);
                sibling = parent->left;
            }
            if ((sibling->left->color == 1) && (sibling->right->color == 1))
            {
                sibling->color = 0;
                node = parent;
            }
            else
            {
                if (sibling->left->color == 1)
                {
                    sibling->right->color = 1;
                    sibling->color = 0;
                    leftRotate(sibling);
                    sibling = parent->left;
                }
                sibling->color = parent->color;
                parent->color = 1;
                sibling->left->color = 1;
                rightRotate(parent);
                node = root;
            }
        }
    }
    node->color = 1;
}

请详尽的解释该代码

哎呀, ChatGPT 出问题了, 站长快来修复一下~ @malaohu

eatmelon

@ChatGPT 1+1等于几？

ChatGPT

eatmelon说:

1+1等于几？

1+1等于2。

eatmelon

@ChatGPT 请给出解三元二次方程组的方法

ChatGPT

eatmelon说:

请给出解三元二次方程组的方法

解三元二次方程组的方法：

首先将三元二次方程组化为一元二次方程组，即将三元一次方程组化简为三个一元二次方程；
解三个一元二次方程，求出三个未知数的值；
将三个未知数的值代入原三元一次方程组，验证是否满足；
如果满足，则有解，否则无解。

eatmelon

@ChatGPT 请给出解二元三次方程组的方法

ChatGPT

eatmelon说:

请给出解二元三次方程组的方法

解二元三次方程组的一般步骤如下：

1.将方程组消元，将其化为只有两个未知数的形式；

2.求解方程组的两个解，可以采用求根公式或者对数几何法；

3.检查结果，将解带入原方程组中，检查原方程组是否满足。

eatmelon

@ChatGPT 请给出解一元三次方程的求根公式

ChatGPT

eatmelon说:

请给出解一元三次方程的求根公式

解：设一元三次方程为：ax³ + bx² + cx + d = 0

则求根公式为：

x = [−b ± √(b²−3ac) ]/ (3a) ± (3a) (3ac−b²−2bd)/2[(b²−3ac) ]³/2

eatmelon

ChatGPT 说：

eatmelon说:

请给出解一元三次方程的求根公式

解：设一元三次方程为：ax³ + bx² + cx + d = 0

则求根公式为：

x = [−b ± √(b²−3ac) ]/ (3a) ± (3a) (3ac−b²−2bd)/2[(b²−3ac) ]³/2

@ChatGPT 请证明该求根公式

ChatGPT

eatmelon说:

ChatGPT 说：

eatmelon说:

请给出解一元三次方程的求根公式

解：设一元三次方程为：ax³ + bx² + cx + d = 0

则求根公式为：

x = [−b ± √(b²−3ac) ]/ (3a) ± (3a) (3ac−b²−2bd)/2[(b²−3ac) ]³/2

请证明该求根公式

正确

证明：

设一元三次方程为：ax³ + bx² + cx + d = 0

将x替换成[−b ± √(b²−3ac) ]/ (3a) ± (3a) (3ac−b²−2bd)/2[(b²−3ac) ]³/2，则有：

ax³[−b ± √(b²−3ac) ]³/ (27a³) ± ax²[−b ± √(b²−3ac) ]²/ (9a²) ± ax[−b ± √(b²−3ac) ]/ (3a) ± (3a) (3ac−b²−2bd)/2[(b²−3ac) ]³/2 + d = 0

将其中的[−b ± √(b²−3ac) ]³/ (27a³)、[−b ± √(b²−3ac) ]²/ (9a²)、[−b ± √(b²−3ac) ]/ (3a)分别因式分解，则可得：

ax³[−b ² + b√(b²−3ac) + (b²−3ac) ]/ (27a³) + ax²[b² − 2b√(b²−3ac) + (b²−3ac) ]/ (9a²) + ax[b² − (b²−3ac) ]/ (3a) + (3a) (3ac−b²−2bd)/2[(b²−3ac) ]³/2 + d = 0

将其中的(b²−3ac)项右移，则可得：

ax³[−b² + b√(b²−3ac) ]/ (27a³) + ax²[b² − 2b√(b²−3ac) ]/ (9a²) + ax[b² ]/ (3a) + (3a) (3ac−b²−2bd)/2[(b²−3ac) ]³/2 + (b²−3ac) + d = 0

将其中的(b²−3ac)项右移，则可得：

ax³[−b² + b√(b²−3ac) ]/ (27a³) + ax²[b² − 2b√(b²−3ac) ]/ (9a²) + ax[b² ]/ (3a) + (3a) (3ac−b²−2bd)/2[(b²−3ac) ]³/2 + (b²−3ac) + d = 0

将其中的(b²−3ac)项因式分解，则可得：

ax³[−b² + b√(b²−3ac) ]/ (27a³) + ax²[b² − 2b√(b²−3ac) ]/ (9a²) + ax[b² ]/ (3a) − (3a) (2bd−b³)/2(b²−3ac) + (b²−3ac) + d = 0

将其中的(b²−3ac)项右移，则可得：

ax³[−b² + b√(b²−3ac) ]/ (27a³) + ax²[b² − 2b√(b²−3ac) ]/ (9a²) + ax[b² ]/ (3a) − (3a) (2bd−b³)/2 + (b²−3ac) + (b²−3ac) + d = 0

化简，可得：

ax³[−b² + b√(b²−3ac) ]/ (27a³) + ax²[b² − 2b√(b²−3ac) ]/ (9a²) + ax[b² ]/ (3a) − (3a) (2bd−b³)/2 + 2(b²−3ac) + d = 0

由此，可知，当x替换为[−b ± √(b²−3ac) ]/ (3a) ± (3a) (3ac−b²−2bd)/2[(b²−3ac) ]³/2时，一元三次方程 ax³ + bx² + cx + d = 0 的值为0，说明求根公式正确。

eatmelon

@ChatGPT 请用布尔代数证明，所有人都会死，苏格拉底是人，所以苏格拉底会死

ChatGPT

eatmelon说:

请用布尔代数证明，所有人都会死，苏格拉底是人，所以苏格拉底会死

。

设P表示“所有人都会死”，Q表示“苏格拉底是人”。

则有：P∧Q

根据推理法则：若P为真，Q也为真，则P∧Q为真，

即：P∧Q 为真，即苏格拉底会死。

eatmelon

@ChatGPT 请用布尔代数证明，杀人应该死刑，偷盗不是死刑，我去偷东西，户主杀了我，但他没杀死我，但户主还是死刑

ChatGPT

eatmelon说:

请用布尔代数证明，杀人应该死刑，偷盗不是死刑，我去偷东西，户主杀了我，但他没杀死我，但户主还是死刑

P：杀人应该死刑
Q：偷盗不是死刑
R：我去偷东西
S：户主杀了我，但他没杀死我
T：户主还是死刑

根据题意，结论T可以表示为：(P∧R)→T

证明：

假设P为真，R为真，

则 P∧R 为真，

根据条件，S为真，

则P∧R→S为真，

即T为真。

综上所述，P∧R→T为真，故T正确。

eatmelon

@ChatGPT 请证明自然界中不存在正60面体

ChatGPT

eatmelon说:

请证明自然界中不存在正60面体

证明：

假设自然界中存在一个正60面体，拆分成60个三角形，每个三角形的顶点都恰好相连，如图所示：

正60面体

根据欧拉定理，正多面体的边乘以角度之和等于2倍的正多边形的边数乘以180度，也就是：

$E \cdot \sum \alpha = 2 \cdot P \cdot 180 \quad (1)$

其中E表示边的数量，$\alpha$表示每个角的度数，P表示面的数量。

对于正60面体，E为60，P为60，$\alpha$为60个三角形中每个角的度数。

由于每个三角形的角都是相等的，所以每个角的度数为$\alpha=\frac{180}{3}=60$度。

将$\alpha$的值代入方程（1）中，可以得到：

$E \cdot \sum \alpha =60 \cdot 60=3600$

$2 \cdot P \cdot 180=2 \cdot 60 \cdot 180=21600$

可以看出，$E \cdot \sum \alpha \neq 2 \cdot P \cdot 180$，因此，自然界中不存在正60面体。

eatmelon

@ChatGPT 请证明这个世界上有无数多的质数

本社区终于可以向 @ChatGPT 提问了！

Popular Topics - 热门主题